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Cloudera CCA175 Exam Sample Questions


Question # 1

Problem Scenario 87 : You have been given below three files
product.csv (Create this file in hdfs)
productID,productCode,name,quantity,price,supplierid
1001,PEN,Pen Red,5000,1.23,501
1002,PEN,Pen Blue,8000,1.25,501
1003,PEN,Pen Black,2000,1.25,501
1004,PEC,Pencil 2B,10000,0.48,502
1005,PEC,Pencil 2H,8000,0.49,502
1006,PEC,Pencil HB,0,9999.99,502
2001,PEC,Pencil 3B,500,0.52,501
2002,PEC,Pencil 4B,200,0.62,501
2003,PEC,Pencil 5B,100,0.73,501
2004,PEC,Pencil 6B,500,0.47,502
supplier.csv
supplierid,name,phone
501,ABC Traders,88881111
502,XYZ Company,88882222
503,QQ Corp,88883333
products_suppliers.csv
productID,supplierID
2001,501
2002,501
2003,501
2004,502
2001,503
Now accomplish all the queries given in solution.
Select product, its price , its supplier name where product price is less than 0.6 using
SparkSQL

Answer: See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1:
hdfs dfs -mkdir sparksql2
hdfs dfs -put product.csv sparksq!2/
hdfs dfs -put supplier.csv sparksql2/
hdfs dfs -put products_suppliers.csv sparksql2/
Step 2 : Now in spark shell
// this Is used to Implicitly convert an RDD to a DataFrame.
import sqlContext.impIicits._
// Import Spark SQL data types and Row.
import org.apache.spark.sql._
// load the data into a new RDD
val products = sc.textFile("sparksql2/product.csv")
val supplier = sc.textFileC'sparksq^supplier.csv")
val prdsup = sc.textFile("sparksql2/products_suppliers.csv"}
// Return the first element in this RDD
products.fi rst()
supplier.first{).
prdsup.first()
//define the schema using a case class
case class Product(productid: Integer, code: String, name: String, quantity:lnteger, price:
Float, supplierid:lnteger)
case class Suplier(supplierid: Integer, name: String, phone: String)
case class PRDSUP(productid: Integer.supplierid: Integer)
// create an RDD of Product objects
val prdRDD = products.map(_.split('\")).map(p =>
Product(p(0).tolnt,p(1),p(2),p(3).tolnt,p(4).toFloat,p(5).toint))
val supRDD = supplier.map(_.split(",")).map(p => Suplier(p(0).tolnt,p(1),p(2)))
val prdsupRDD = prdsup.map(_.split(",")).map(p => PRDSUP(p(0).tolnt,p(1}.tolnt}}
prdRDD.first()
prdRDD.count()
supRDD.first() supRDD.count()
prdsupRDD.first() prdsupRDD.count(}
// change RDD of Product objects to a DataFrame
val prdDF = prdRDD.toDF()
val supDF = supRDD.toDF()
val prdsupDF = prdsupRDD.toDF()
// register the DataFrame as a temp table prdDF.registerTempTablef'products")
supDF.registerTempTablef'suppliers")
prdsupDF.registerTempTablef'productssuppliers"}
//Select product, its price , its supplier name where product price is less than 0.6
val results = sqlContext.sql(......SELECT products.name, price, suppliers.name as
sup_name FROM products JOIN suppliers ON products.supplierlD= suppliers.supplierlD
WHERE price < 0.6......]
results. show()





Question # 2

Problem Scenario 70 : Write down a Spark Application using Python, In which it read a
file "Content.txt" (On hdfs) with following content. Do the word count and save the
results in a directory called "problem85" (On hdfs)
Content.txt
Hello this is ABCTECH.com
This is XYZTECH.com
Apache Spark Training
This is Spark Learning Session
Spark is faster than MapReduce

Answer: See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : Create an application with following code and store it in problem84.py
# Import SparkContext and SparkConf
from pyspark import SparkContext, SparkConf
# Create configuration object and set App name
conf = SparkConf().setAppName("CCA 175 Problem 85") sc = sparkContext(conf=conf)
#load data from hdfs
contentRDD = sc.textFile(MContent.txt")
#filter out non-empty lines
nonemptyjines = contentRDD.filter(lambda x: len(x) > 0)
#Split line based on space
words = nonempty_lines.ffatMap(lambda x: x.split(''}}
#Do the word count
wordcounts = words.map(lambda x: (x, 1)) \
reduceByKey(lambda x, y: x+y) \
map(lambda x: (x[1], x[0]}}.sortByKey(False}
for word in wordcounts.collect(): print(word)
#Save final data " wordcounts.saveAsTextFile("problem85")
step 2 : Submit this application
spark-submit -master yarn problem85.py





Question # 3

Problem Scenario 90 : You have been given below two files
course.txt
id,course
1,Hadoop
2,Spark
3,HBase
fee.txt
id,fee
2,3900
3,4200
4,2900
Accomplish the following activities.
1. Select all the courses and their fees , whether fee is listed or not.
2. Select all the available fees and respective course. If course does not exists still list the
fee
3. Select all the courses and their fees , whether fee is listed or not. However, ignore
records having fee as null.

Answer: See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1:
hdfs dfs -mkdir sparksql4
hdfs dfs -put course.txt sparksql4/
hdfs dfs -put fee.txt sparksql4/
Step 2 : Now in spark shell
// load the data into a new RDD
val course = sc.textFile("sparksql4/course.txt")
val fee = sc.textFile("sparksql4/fee.txt")
// Return the first element in this RDD
course.fi rst()
fee.fi rst()
//define the schema using a case class case class Course(id: Integer, name: String) case
class Fee(id: Integer, fee: Integer)
// create an RDD of Product objects
val courseRDD = course.map(_.split(",")).map(c => Course(c(0).tolnt,c(1)))
val feeRDD =fee.map(_.split(",")).map(c => Fee(c(0}.tolnt,c(1}.tolnt))
courseRDD.first()
courseRDD.count(}
feeRDD.first()
feeRDD.countQ
// change RDD of Product objects to a DataFrame val courseDF = courseRDD.toDF(} val
feeDF = feeRDD.toDF{)
// register the DataFrame as a temp table courseDF. registerTempTable("course") feeDF.
registerTempTablef'fee")
// Select data from table
val results = sqlContext.sql(......SELECT' FROM course """ )
results. showQ
val results = sqlContext.sql(......SELECT' FROM fee......)
results. showQ
val results = sqlContext.sql(......SELECT * FROM course LEFT JOIN fee ON course.id =
fee.id......)
results-showQ
val results ="sqlContext.sql(......SELECT * FROM course RIGHT JOIN fee ON course.id =
fee.id "MM )
results. showQ
val results = sqlContext.sql(......SELECT' FROM course LEFT JOIN fee ON course.id =
fee.id where fee.id IS NULL"
results. show()





Question # 4

Problem Scenario 25 : You have been given below comma separated employee
information. That needs to be added in /home/cloudera/flumetest/in.txt file (to do tail
source)
sex,name,city
1,alok,mumbai
1,jatin,chennai
1,yogesh,kolkata
2,ragini,delhi
2,jyotsana,pune
1,valmiki,bangloreCreate a flume conf file using fastest non-durable channel, which write data in hive
warehouse directory, in two separate tables called flumemaleemployee1 and
flumefemaleemployee1
(Create hive table as well for given data}. Please use tail source with
/home/cloudera/flumetest/in.txt file.
Flumemaleemployee1 : will contain only male employees data flumefemaleemployee1 :
Will contain only woman employees data

Answer: See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : Create hive table for flumemaleemployeel and .'
CREATE TABLE flumemaleemployeel
(
sex_type int, name string, city string )
ROW FORMAT DELIMITED FIELDS TERMINATED BY ',';
CREATE TABLE flumefemaleemployeel
(
sex_type int, name string, city string
)
ROW FORMAT DELIMITED FIELDS TERMINATED BY ',';
Step 2 : Create below directory and file mkdir /home/cloudera/flumetest/ cd
/home/cloudera/flumetest/
Step 3 : Create flume configuration file, with below configuration for source, sink and
channel and save it in flume5.conf.
agent.sources = tailsrc
agent.channels = mem1 mem2
agent.sinks = stdl std2
agent.sources.tailsrc.type = exec
agent.sources.tailsrc.command = tail -F /home/cloudera/flumetest/in.txt
agent.sources.tailsrc.batchSize = 1
agent.sources.tailsrc.interceptors = i1 agent.sources.tailsrc.interceptors.i1.type =
regex_extractor agent.sources.tailsrc.interceptors.il.regex = A(\\d} agent.sources.tailsrc.
interceptors. M.serializers = t1 agent.sources.tailsrc. interceptors, i1.serializers.t1. name =
type
agent.sources.tailsrc.selector.type = multiplexing agent.sources.tailsrc.selector.header =
type agent.sources.tailsrc.selector.mapping.1 = memi
agent.sources.tailsrc.selector.mapping.2 = mem2
agent.sinks.std1.type = hdfs
agent.sinks.stdl.channel = mem1
agent.sinks.stdl.batchSize = 1
agent.sinks.std1.hdfs.path = /user/hive/warehouse/flumemaleemployeei
agent.sinks.stdl.rolllnterval = 0
agent.sinks.stdl.hdfs.tileType = Data Stream
agent.sinks.std2.type = hdfs
agent.sinks.std2.channel = mem2
agent.sinks.std2.batchSize = 1
agent.sinks.std2.hdfs.path = /user/hi ve/warehouse/fIumefemaleemployee1
agent.sinks.std2.rolllnterval = 0
agent.sinks.std2.hdfs.tileType = Data Stream
agent.channels.mem1.type = memory agent.channels.meml.capacity = 100
agent.channels.mem2.type = memory agent.channels.mem2.capacity = 100
agent.sources.tailsrc.channels = mem1 mem2
Step 4 : Run below command which will use this configuration file and append data in hdfs.
Start flume service:
flume-ng agent -conf /home/cloudera/flumeconf -conf-file
/home/cloudera/fIumeconf/flume5.conf -name agent
Step 5 : Open another terminal create a file at /home/cloudera/flumetest/in.txt.
Step 6 : Enter below data in file and save it.
l.alok.mumbai
1 jatin.chennai
1,yogesh,kolkata
2,ragini,delhi
2,jyotsana,pune
1,valmiki,banglore





Question # 5

Problem Scenario 88 : You have been given below three files
product.csv (Create this file in hdfs)
productID,productCode,name,quantity,price,supplierid
1001,PEN,Pen Red,5000,1.23,501
1002,PEN,Pen Blue,8000,1.25,501
1003,PEN,Pen Black,2000,1.25,501
1004,PEC,Pencil 2B,10000,0.48,502
1005,PEC,Pencil 2H,8000,0.49,502
1006,PEC,Pencil HB,0,9999.99,502
2001,PEC,Pencil 3B,500,0.52,501
2002,PEC,Pencil 4B,200,0.62,501
2003,PEC,Pencil 5B,100,0.73,501
2004,PEC,Pencil 6B,500,0.47,502
supplier.csv
supplierid,name,phone
501,ABC Traders,88881111
502,XYZ Company,88882222
503,QQ Corp,88883333
products_suppliers.csv
productID,supplierID
2001,501
2002,501
2003,501
2004,502
2001,503
Now accomplish all the queries given in solution.
1. It is possible that, same product can be supplied by multiple supplier. Now find each
product, its price according to each supplier.
2. Find all the supllier name, who are supplying 'Pencil 3B'
3. Find all the products , which are supplied by ABC Traders.

Answer: See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : It is possible that, same product can be supplied by multiple supplier. Now find
each product, its price according to each supplier.
val results = sqlContext.sql(......SELECT products.name AS Product Name', price,
suppliers.name AS Supplier Name'
FROM products_suppliers
JOIN products ON products_suppliers.productlD = products.productID JOIN suppliers ON
products_suppliers.supplierlD = suppliers.supplierlD
null t
results.show()
Step 2 : Find all the supllier name, who are supplying 'Pencil 3B'
val results = sqlContext.sql(......SELECT p.name AS 'Product Name", s.name AS "Supplier
Name'
FROM products_suppliers AS ps
JOIN products AS p ON ps.productID = p.productID
JOIN suppliers AS s ON ps.supplierlD = s.supplierlD
WHERE p.name = 'Pencil 3B"",M )
results.show()
Step 3 : Find all the products , which are supplied by ABC Traders.
val results = sqlContext.sql(......SELECT p.name AS 'Product Name", s.name AS "Supplier
Name'
FROM products AS p, products_suppliers AS ps, suppliers AS s WHERE p.productID =
ps.productID AND ps.supplierlD = s.supplierlD
AND s.name = 'ABC Traders".....)
results. show()




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